(MAT105 -Intro 2 Cllge Math) Real Wrld App #22 -Wk 9

(MAT105 -Intro 2 Cllge Math) Real Wrld App #22 -Wk 9 -...

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In Real World Application # 22, you learn to differentiate between 2 and 3 dimensional shapes. A 3-demensional shape is an extension of a 2-demensional shape. For example, I’m sure everyone is familiar with mobile homes. When you are looking at the floor-plan for a home you may be considering, you will only see the area of the space the foundation will take up (familiarly a rectangle). The actual volume of the house will be much larger. Exercise #3 says : How far along the vertical axis would the circle in Example 3 need to be translated in order for the volume of the generated cylinder to be 1440π in 3 ? ** a circle being translated means it is expanding upward along an axis through its center and becoming 3-demensional. The equation to find the volume of a right circular cylinder is the same format when
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Unformatted text preview: finding the volume of a cubic shape. Find the area of the base and then multiply that by the height. The equation to find the area of a circle is πr 2 . So the equation to find the volume is πr 2 h. The circle in example 3 has a radius of 6 in. and is 10 in. tall. Its volume is 360π in 3 * V = π(6 in.) 2 (10 in.) So to find the height (or how far the base circle is being translated) I filled in the parts of the equation I knew and solved for the height: πr 2 h = 1440π in. 3 π (6 in.) 2 h = 1440π in. 3 or. . (6 in.) 2 h = 1440 π (36 in. 2 ) h = 1440π in. 3 or. . 36 in. 2 (h) = 1440 So, what # of inches multiplied by 36 in. 2 would = 1440 in. 2 ? 36h = 1440 h = 40 in. (36 in. 2 ) (40 in.) π = 1440π in. 3 The height (or distance the circle translated) is 40 in. 6in 6 in. 10in 40 in....
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This note was uploaded on 01/19/2012 for the course MATH XMAT105 taught by Professor Unknown during the Spring '11 term at Strayer.

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(MAT105 -Intro 2 Cllge Math) Real Wrld App #22 -Wk 9 -...

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