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Problem 13.1
[Difficulty: 2]
Given:
Air extracted from a large tank
Find:
Mass flow rate
Solution:
Basic
equations:
m
rate
ρ
V
A
h
1
V
1
2
2
h
2
V
2
2
2
p
ρ
k
const
Tp
1k
()
k
const
Given or available data
T
0
70
273
K
p
0
101 kPa
p
25 kPa
D1
5
c
m
c
p
1004
J
kg K
k
1.4
R
286.9
J
kg K
The mass flow rate is given by
m
rate
ρ
A
V
A
π
D
2
4
A
0.0177 m
2
We need the density and velocity at the nozzle.
In the tank
ρ
0
p
0
RT
0
ρ
0
1.026
kg
m
3
From the isentropic relation
ρρ
0
p
p
0
1
k
ρ
0.379
kg
m
3
We can apply the energy equation between the tank (stagnation conditions) and the point in the nozzle to find the velocity
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This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear

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