This preview shows page 1. Sign up to view the full content.
Problem 13.1 [Difficulty: 2] Given: Air extracted from a large tank Find: Mass flow rate Solution: Basic equations: m rate ρ V A h 1 V 1 2 2 h 2 V 2 2 2 p ρ k const Tp 1k () k const Given or available data T 0 70 273 K p 0 101 kPa p 25 kPa D1 5 c m c p 1004 J kg K k 1.4 R 286.9 J kg K The mass flow rate is given by m rate ρ A V A π D 2 4 A 0.0177 m 2 We need the density and velocity at the nozzle. In the tank ρ 0 p 0 RT 0 ρ 0 1.026 kg m 3 From the isentropic relation ρρ 0 p p 0 1 k ρ 0.379 kg m 3 We can apply the energy equation between the tank (stagnation conditions) and the point in the nozzle to find the velocity
This is the end of the preview. Sign up to access the rest of the document.
This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
- Fall '07