Problem 13.8 - 1 , and Eq. 13.7d (using built-in function...

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Problem 13.8 [Difficulty: 2] Given: Data on flow in a passage Find: Stagnation conditions; whether duct is a nozzle or diffuser; exit conditions Solution: The given or available data is: R = 259.8 J/kg-K k = 1.4 p 1 = 200 kPa T 1 = 420 K V 1 = 200 m/s A 1 = 0.6 m 2 A 2 = 0.5 m 2 Equations and Computations: From T 1 and Eq. 12.18 c 1 = 391 m/s Then M 1 = 0.512 From M 1 and T 1 , and Eq. 13.7b (using built-in function Isent ( M , k )) T 01 = 442 K From M 1 and p 1 , and Eq. 13.7a (using built-in function Isenp ( M , k )) p 01 = 239 kPa Since the flow is subsonic and the area is decreasing, this duct is a nozzle. From M
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Unformatted text preview: 1 , and Eq. 13.7d (using built-in function IsenA ( M , k )) A * 1 = 0.4552 m 2 For isentropic flow ( p 01 = p 02 , T 01 = T 02, A * 2 = A * 1 ) p 02 = 239 kPa T 02 = 442 K A * 2 = 0.4552 m 2 A 2 /A * 2 = 1.0984 From A 2 / A * 2 , and Eq. 13.7d (using built-in function IsenMsubfromA ( M , k )) Since there is no throat, the flow stays subsonic! M 2 = 0.69 From M 2 and stagnation conditions: (using built-in functions) p 2 = 173 kPa T 2 = 403 K...
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This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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