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Problem 13.8
[Difficulty: 2]
Given:
Data on flow in a passage
Find:
Stagnation conditions; whether duct is a nozzle or diffuser; exit conditions
Solution:
The given or available data is:
R
=
259.8
J/kgK
k
=
1.4
p
1
=
200
kPa
T
1
=
420
K
V
1
=
200
m/s
A
1
=
0.6
m
2
A
2
=
0.5
m
2
Equations and Computations:
From
T
1
and Eq. 12.18
c
1
=
391
m/s
Then
M
1
=
0.512
From
M
1
and
T
1
, and Eq. 13.7b
(using builtin function
Isent
(
M
,
k
))
T
01
=
442
K
From
M
1
and
p
1
, and Eq. 13.7a
(using builtin function
Isenp
(
M
,
k
))
p
01
=
239
kPa
Since the flow is subsonic and the area is decreasing, this duct is a nozzle.
From
M
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Unformatted text preview: 1 , and Eq. 13.7d (using builtin function IsenA ( M , k )) A * 1 = 0.4552 m 2 For isentropic flow ( p 01 = p 02 , T 01 = T 02, A * 2 = A * 1 ) p 02 = 239 kPa T 02 = 442 K A * 2 = 0.4552 m 2 A 2 /A * 2 = 1.0984 From A 2 / A * 2 , and Eq. 13.7d (using builtin function IsenMsubfromA ( M , k )) Since there is no throat, the flow stays subsonic! M 2 = 0.69 From M 2 and stagnation conditions: (using builtin functions) p 2 = 173 kPa T 2 = 403 K...
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This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear

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