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Unformatted text preview: c 1 = 352.9 m/s c 2 = 343.6 m/s V 1 = 109.8 m/s V 2 = 210.2 m/s Since flow is steady, the mass flow rate must be equal at 1 and 2. So the area ratio may be calculated from the densities and velocities: A 2 /A 1 = 0.792 Note that we can not assume isentropic flow in this problem. While the flow is adiabatic, it is not reversible. There is a drop in stagnation pressure from state 1 to 2 which would invalidate the assumption of isentropic flow....
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This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
- Fall '07