Problem 13.16 - = 27.2 kg/s From M 1 and A 1 , and Eq....

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Problem 13.16 [Difficulty: 2] Given: Data on flow in a passage Find: Flow rate; area and pressure at downstream location; sketch passage shape Solution: The given or available data is: R = 286.9 J/kg.K k = 1.4 A 1 = 0.25 m 2 T 1 = 283 K p 1 = 15 kPa V 1 = 590 m/s T 2 = 410 M 2 = 0.75 Equations and Computations: From T 1 and Eq. 12.18 (12.18) c 1 = 337 m/s Then M 1 = 1.75 Because the flow decreases isentropically from supersonic to subsonic the passage shape must be convergent-divergent From p 1 and T 1 and the ideal gas equation 1 = 0.185 kg/m 3 The mass flow rate is m rate = 1 A 1 V 1 m rate
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Unformatted text preview: = 27.2 kg/s From M 1 and A 1 , and Eq. 13.7d (using built-in function IsenA ( M , k )) (13.7d) A* = 0.180 m 2 From M 2 and A *, and Eq. 13.7d (using built-in function IsenA ( M , k )) A 2 = 0.192 m 2 From M 1 and p 1 , and Eq. 13.7a (using built-in function Isenp ( M , k )) (13.7a) p 01 = 79.9 kPa For isentropic flow ( p 01 = p 02 ) p 02 = 79.9 kPa From M 2 and p 02 , and Eq. 13.7a (using built-in function Isenp ( M , k )) p 2 = 55.0 kPa...
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Problem 13.16 - = 27.2 kg/s From M 1 and A 1 , and Eq....

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