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Unformatted text preview: Isenp ( M , k ) (13.7a) Then p 1 = 150 kPa The mass flow rate is m rate = 1 A 1 V 1 Hence, we need 1 from the ideal gas equation. 1 = 1.89 kg/m 3 The mass flow rate m rate is then m rate = 18.9 kg/s The throat area A t = A * because the flow is choked. From M 1 and A 1 , and Eq. 13.7d (using built-in function IsenA ( M , k ) (13.7d) A* = 0.0421 m 2 Hence A t = 0.0421 m 2...
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- Fall '07