Problem 13.28 - Problem 13.28[Difficulty 3 Given Data on flow in a passage Find Exit temperature and mass flow rate of air assuming isentropic flow

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Problem 13.28 [Difficulty: 3] Given: Data on flow in a passage Find: Exit temperature and mass flow rate of air assuming isentropic flow Solution: The given or available data is: R = 53.33 ft-lbf/lbm- ° R k = 1.4 T 1 = 450 °R p 1 = 45 psia p 01 = 51 psia A 1 =4 ft 2 A 2 =3 ft 2 Equations and Computations: From the static and stagnation pressures we can calculate M 1 : M 1 = 0.427 From the M 1 and T 1 we can get T 01 : T 01 = 466.38 °R From M 1 , and Eq. 13.7d (using built-in function IsenA ( M , k )) A * 1 = 2.649 ft 2 For isentropic flow ( p 02 = p 01 , T 02 = T 01 , A * 2 = A * 1 ) p 02 = 51 psia T 02 = 466.38 °R A * 2 = 2.649 ft 2 A 2 /A * 2 = 1.1325
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Given subsonic flow in the duct, we can find the exit Mach number using
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This note was uploaded on 01/20/2012 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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Problem 13.28 - Problem 13.28[Difficulty 3 Given Data on flow in a passage Find Exit temperature and mass flow rate of air assuming isentropic flow

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