Problem 13.37 - Problem 13.37 [Difficulty: 3] Given:...

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Problem 13.37 [Difficulty: 3] Given: Air-driven rocket in space Find: Tank pressure; pressure, temperature and speed at exit; initial acceleration Solution: The given or available data is: R = 286.9 J/kg.K k = 1.4 T 0 = 398 K A t =2 5 mm 2 M = 25 kg m rate = 0.05 kg/s Equations and Computations: Because p b = 0 p e = p * Hence the flow is choked! Hence T e = T * From T 0 , and Eq. 12.22b (12.22b) T * = 332 K T e = 332 K 58.7 o C Also M e =1 Hence V e = V * = c e From T e and Eq. 12.18 (12.18) c e = 365 m/s Then V e = 365 m/s
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To find the exit pressure we use the ideal gas equation after first finding the exit density. The mass flow rate is
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Problem 13.37 - Problem 13.37 [Difficulty: 3] Given:...

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