4.9 - 4 4.9 System = contents of the turbine. This is a...

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4.9 System = contents of the turbine. This is a steady-state, adiabatic, constant volume system. (a) Mass balance dM dt MM == + 0 12 ±± or 21 =− Energy balance dU dt MH + + 0 11 2 2 ± ² ± ² ± Q adiabatic +− ± WP s dV dt constant volume Entropy balance dS dt MS + + 0 ± ² ± ² ± Q T + S gen 0, by problem statement Thus 4500 kg h M.B. E . B . ²² WM H H S 2 ch 1 S . B . SS 2 = State 1 T 1 500 C P 1 60 = bar Tables Steam ⎯→ ⎯⎯⎯ ² . H 1 3422 2 = kJ kg ² . S 1 68803 = State 2 P 2 10 = bar . 68803 kJ kgK Tables Steam T 2 2404 ° .C ² . H 2 29205 ± .. . W s =×− () 4500 29205 3422 2 2257650 6271 kg h kJ kg kJ h kW (b) Same exit pressure , and still adiabatic P 2 10 bar = af ⇒= . H H s 2 Here, however, ± . ± ² . WW H ss = =− × = 08 2 258 10 4500 3422 2 6 2 Part a kJ h kJ h = = ² . H P 2 30208 10 bar kJ kg Tables Steam T S 2 2 2867 70677 . ² . K kJ kg K Thus . SM S S gen kg h kJ kg K kJ Kh × = 2 4500 68803 7 0677 8433 (c) Flow across valve is a Joule-Thompson (isenthalpic expansion) . .. See Illustration 3.4-1. Thus, , and the inlet conditions to the turbine are
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4.9 - 4 4.9 System = contents of the turbine. This is a...

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