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Unformatted text preview: for h in equation (2.5) and substituting that into equation (2.4) gives a sin B b = sin A , (2.6) and so putting a and A on the left side and b and B on the right side, we get a sin A = b sin B . (2.7) By a similar argument, drawing the altitude from A to BC gives b sin B = c sin C , (2.8) so putting the last two equations together proves the theorem. QED Note that we did not prove the Law of Sines for right triangles, since it turns out (see Exercise 12) to be trivially true for that case. 1 Recall from geometry that an altitude of a triangle is a perpendicular line segment from any vertex to the line containing the side opposite the vertex....
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This note was uploaded on 01/21/2012 for the course MAC 1130 taught by Professor Dr.cheun during the Fall '11 term at FSU.
 Fall '11
 Dr.Cheun
 Calculus, Angles

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