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Unformatted text preview: 40 Chapter 2 General Triangles 2.1 Example 2.1 b a = 10 c A = 41 B C = 75 Case 1: One side and two angles. Solve the triangle ABC given a = 10, A = 41 , and C = 75 . Solution: We can find the third angle by subtracting the other two angles from 180 , then use the law of sines to find the two unknown sides. In this example we need to find B , b , and c . First, we see that B = 180 A C = 180 41 75 B = 64 . So by the Law of Sines we have b sin B = a sin A b = a sin B sin A = 10 sin 64 sin 41 b = 13.7 , and c sin C = a sin A c = a sin C sin A = 10 sin 75 sin 41 c = 14.7 . Example 2.2 b = 30 a = 18 c A = 25 B C Case 2: Two sides and one opposite angle. Solve the triangle ABC given a = 18, A = 25 , and b = 30. Solution: In this example we know the side a and its opposite angle A , and we know the side b . We can use the Law of Sines to find the other opposite angle B , then find the third angle...
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This note was uploaded on 01/21/2012 for the course MAC 1130 taught by Professor Dr.cheun during the Fall '11 term at FSU.
 Fall '11
 Dr.Cheun
 Calculus, Angles

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