Unformatted text preview: 0.775 rad ⇒ ∠ CBD = 2(0.775) = 1.550 rad Thus, the area K is K = (Area of segment CD in circle at A ) + (Area of segment CD in circle at B ) = 1 2 (5) 2 (1.188 − sin 1.188) + 1 2 (4) 2 (1.550 − sin 1.550) = 7.656 cm 2 . Exercises For Exercises 13, ±nd the area of the sector for the given angle θ and radius r . 1. θ = 2.1 rad, r = 1.2 cm 2. θ = 3 π 7 rad, r = 3.5 ft 3. θ = 78 ◦ , r = 6 m 4. The centers of two belt pulleys, with radii of 3 cm and 6 cm, respectively, are 13 cm apart. Find the total area K enclosed by the belt. 5. In Exercise 4 suppose that both belt pulleys have the same radius of 6 cm. Find the total area K enclosed by the belt....
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 Fall '11
 Dr.Cheun
 Calculus

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