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Unformatted text preview: .., since it will be understood that k varies over all integers. The general solution in radians would be: A = 0.6435 + k for k = 0, 1, 2, . .. Example 6.1 Solve the equation 2 sin + 1 = 0. Solution: Isolating sin gives sin = 1 2 . Using the a sin 1 calculator button in degree mode gives us = 30 , which is in QIV. Recall that the reection of this angle around the yaxis into QIII also has the same sine. That is, sin 210 = 1 2 . Thus, since the sine function has period 2 rad = 360 , and since 30 does not differ from 210 by an integer multiple of 360 , the general solution is: = 30 + 360 k and 210 + 360 k for k = 0, 1, 2, . .. In radians, the solution is: = 6 + 2 k and 7 6 + 2 k for k = 0, 1, 2, . .. For the rest of this section we will write our solutions in radians. 129...
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This note was uploaded on 01/21/2012 for the course MAC 1130 taught by Professor Dr.cheun during the Fall '11 term at FSU.
 Fall '11
 Dr.Cheun
 Calculus, Addition, Equations

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