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Differential Equations Solutions 23

Differential Equations Solutions 23 - Chapter 6 Solutions...

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Chapter 6 Solutions: Case Study: Image Deblurring: I Can See Clearly Now (coauthored by James G. Nagy) CHALLENGE 6.1. Observe that if y is a p × 1 vector and z is a q × 1 vector then y z 2 2 = p i =1 y 2 i + q i =1 z 2 i = y 2 2 + z 2 2 . Therefore, g 0 K α I f 2 2 = g Kf α f 2 2 = g Kf 2 2 + α f 2 2 = g Kf 2 2 + α 2 f 2 2 . CHALLENGE 6.2. First note that Q U T 0 0 V T is an orthogonal matrix since
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