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Unformatted text preview: results are much better than those of Challenge 2, with errors at most 10 14 and no trouble when the pitch is close to vertical. CHALLENGE 12.5. We compute B QA te T 2 F = m X i =1 n X j =1 ( B QA ) 2 ij 2 t i ( B QA ) ij + nt 2 i , and setting the partial derivative with respect to t i to zero yields t i = 1 n n X j =1 ( B QA ) ij ....
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This note was uploaded on 01/21/2012 for the course MAP 3302 taught by Professor Dr.robin during the Fall '11 term at University of Florida.
 Fall '11
 Dr.Robin

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