Differential Equations Solutions 103

Differential Equations Solutions 103 - gives τ(1 − τ 2...

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113 0 20 40 60 80 100 0 100 200 300 400 Percent infected Number of trials Histogram of infection rate for nu = 0.000000 0 10 20 30 40 0 50 100 150 200 Percent infected Histogram of infection rate for nu = 0.100000 0 5 10 15 20 0 50 100 150 200 250 Percent infected Histogram of infection rate for nu = 0.200000 0 5 10 15 20 0 50 100 150 200 250 300 350 Percent infected Histogram of infection rate for nu = 0.300000 Figure 19.4. Results of 1000 trials for a 10 × 10 grid of hospital beds, with infection rate τ =0 . 2 and vaccination rate ν ,w i th ν
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Unformatted text preview: gives ( τ (1 − τ ) 2 + τ (1 − τ ) 3 ). The probability of reaching state P is the same, so the probability of 2 infections is twice this number. Similarly, the probability of reaching state R, corresponding to 3 infections, is τ 2 + 2 τ 2 (1 − τ ) + (1 − τ ) 2 τ 2 . The probabilities of reaching states P, Q, R, and S sum to one, since these are the only possible outcomes....
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