Differential Equations Solutions 137

# Differential Equations Solutions 137 - p = J F x = x p end...

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Chapter 24 Solutions: Nonlinear Systems CHALLENGE 24.1. F ( x )= · x 2 y 3 + xy 2 2 xy 2 + x 2 y + xy ¸ and J ( x )= · 2 xy 3 + y 3 x 2 y 2 + x 2 y 2 +2 xy + y 4 xy + x 2 + x ¸ . x = [5;4]; for i=1:5, F = [x(1)^2*x(2)^3 + x(1)*x(2) - 2; 2*x(1)*x(2)^2 + x(1)^2*x(2) + x(1)*x(2)]; J = [2*x(1)*x(2)^3 + x(2), 3*x(1)^2*x(2)^2 + x(1); 2*x(2)^2 + 2*x(1)*x(2) + x(2), 4*x(1)*x(2) + x(1)^2 + x(1)];
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Unformatted text preview: p = - ( J \ F ); x = x + p; end CHALLENGE 24.2. • The frst line does n 2 divisions. It would be better to add parentheses to drop this to n : B = B + (y-B*s)*(s’/(s’*s)) . 147...
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## This note was uploaded on 01/21/2012 for the course MAP 3302 taught by Professor Dr.robin during the Fall '11 term at University of Florida.

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