Thermodynamics HW Solutions 490

Thermodynamics HW Solutions 490 - Chapter 5 Numerical...

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Chapter 5 Numerical Methods in Heat Conduction where k = 0.84 W/m. ° C, , T αρ == × kC /. 039 10 6 m/ s 2 i = T o = -3°C h i = 6 W/m 2 . ° C, h o = 20 W/m 2 . ° C, Δ x = 0.002 m, and Δ y = 0.01 m. Taking time step to be Δ t = 1 min, the temperature distribution throughout the glass 15 min after the strip heaters are turned on and when steady conditions are reached are determined to be (from the EES solutions disk) 15 min: T 1 = -2.4
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This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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