Thermodynamics HW Solutions 535

# Thermodynamics HW Solutions 535 - Chapter 6 Fundamentals of...

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Chapter 6 Fundamentals of Convection B.C. 2: y = L k T C T L T 2 ) ( 2 0 4 0 V μ + = ⎯→ = Substituting the constants give the temperature distribution to be μ + = 2 2 2 0 1 2 ) ( L y k T y T V The temperature gradient is determined by differentiating T ( y ) with respect to y , y kL dy dT 2 2 V μ = .The heat flux at the upper surface is L L kL k dy dT k q L y L 2 2 2 V V μ = μ = = = Noting that heat transfer along the shaft is negligible, all the heat generated in the oil is transferred to the shaft, and the rate of heat transfer is W 98.1 = = = = m 001 . 0 m/s) 78 . 11 )( s/m N (0.03 m) m)(0.15 05 . 0 ( ) ( 2 2 2 π L DW q A Q L s V (b) This is equivalent to the rate of heat transfer through the cylindrical sleeve by conduction, which is
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## This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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