Unformatted text preview: surface because of the constant agitation of the engine block. Using the proper relations, the Nusselt number, the heat transfer coefficient, and the heat transfer rate are determined to be C . W/m 98 . 70 ) 2076 ( m 8 . C W/m. 02735 . 2076 ) 7228 . ( ) 10 888 . 9 ( 037 . Pr Re 037 . 2 3 / 1 8 . 5 3 / 1 8 . ° = ° = = = × = = = Nu L k h k hL Nu L W 1363 = C 20))(80 m C)(0.32 . W/m 98 . 70 ( ) ( m 0.32 = m) m)(0.4 8 . ( 2 2 2 ° ° = − = = = ∞ s s conv s T T hA Q wL A & The radiation heat transfer from the same surface is W 132 = × = − = ] K) 273 + (25K) 273 + )[(80 .K W/m 10 )(5.67 m 32 . )( 95 . ( ) ( 4 4 4 28 2 4 4 surr s s rad T T A Q σε & Then the total rate of heat transfer from that surface becomes W 1495 = + = + = W ) 132 1363 ( rad conv total Q Q Q & & & 710...
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 Fall '10
 Dr.DanielArenas
 Thermodynamics, Convection, Force, Mass, Heat, Heat Transfer, critical Reynolds number, engine block

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