Thermodynamics HW Solutions 597

Thermodynamics HW Solutions 597 - Chapter 7 External Forced...

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Chapter 7 External Forced Convection For this staggered tube bank, the friction coefficient corresponding to Re D = 9075 and S T / D = 5/2.1 = 2.38 is, from Fig. 7-27ba, f = 0.34. Also, χ = 1 for the square arrangements. Then the pressure drop across the tube bank becomes Pa 70.3 = = ρ χ = Δ 2 2 3 2 max m/s kg 1 N 1 2 m/s) 552 . 6 )( kg/m 204 . 1 ( ) 1 )( 34 . 0 ( 8 2 V f N P L Discussion The arithmetic mean fluid temperature is ( T i + T e )/2 = (15 +28.3)/2 = 21.7 ° C, which is fairly close to the assumed value of 20 ° C. Therefore, there is no need to repeat calculations. 7-66 Combustion air is heated by condensing steam in a tube bank. The rate of heat transfer to air, the pressure drop of air, and the rate of condensation of steam are to be determined. Assumptions 1 Steady operating conditions exist. 2 The surface temperature of the tubes is equal to the temperature of steam. Properties
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This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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