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Unformatted text preview: friction factor and the pressure drop become kPa 188 V = = = = = = 2 2 3 2 kN/m 1 kPa 1 m/s kg 1000 kN 1 2 m/s) 2 . 1 )( kg/m 7 . 999 ( m 0.002 m 15 0349 . 2 0349 . 1836 64 Re 64 m D L f P f Water 1.2 m/s L = 15 m D = 0.2 cm ( b ) The volume flow rate and the pumping power requirements are W 0.71 V V = = = = = = = /s m kPa 1 W 1000 ) kPa 188 )( / m 10 77 . 3 ( / m 10 77 . 3 ] 4 / m) (0.002 m/s)[ 2 . 1 ( ) 4 / ( 3 3 6 pump 3 6 2 2 s P V W s D A V m c m & & & Therefore, power input in the amount of 0.71 W is needed to overcome the frictional losses in the flow due to viscosity. 811...
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This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Convection, Force, Mass, Power

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