Thermodynamics HW Solutions 652

# Thermodynamics HW Solutions 652 - D_h=(4*A_c)/p A_c=side^2...

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Chapter 8 Internal Forced Convection "GIVEN" T_i=85 "[C]" L=10 "[m]" side=0.15 "[m]" "V_dot=0.10 [m^3/s], parameter to be varied" T_s=70 "[C]" "PROPERTIES" Fluid\$='air' C_p=CP(Fluid\$, T=T_ave)*Convert(kJ/kg-C, J/kg-C) k=Conductivity(Fluid\$, T=T_ave) Pr=Prandtl(Fluid\$, T=T_ave) rho=Density(Fluid\$, T=T_ave, P=101.3) mu=Viscosity(Fluid\$, T=T_ave) nu=mu/rho T_ave=1/2*(T_i+T_e) "ANALYSIS"
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Unformatted text preview: D_h=(4*A_c)/p A_c=side^2 p=4*side Vel=V_dot/A_c Re=(Vel*D_h)/nu "The flow is turbulent" L_t=10*D_h "The entry length is much shorter than the total length of the duct." Nusselt=0.023*Re^0.8*Pr^0.3 h=k/D_h*Nusselt A=4*side*L m_dot=rho*V_dot T_e=T_s-(T_s-T_i)*exp((-h*A)/(m_dot*C_p)) DELTAT_ln=(T_e-T_i)/ln((T_s-T_e)/(T_s-T_i)) Q_dot=h*A*DELTAT_ln 8-14...
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## This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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