Chapter 8 Internal Forced Convection8-46Turbulent flow of a fluid through an isothermal square channel is considered. The change in the pressure drop and the rate of heat transfer are to be determined when the free-stream velocity is doubled.Analysis The pressure drop of the fluid for turbulent flow is expressed as DLDDLDDLDLfPmmmmmρυ2.08.122.02.02.022.021092.02184.02Re184.02−−−−−⎟⎠⎞⎜⎝⎛====ΔVVVVVWhen the free-stream velocity of the fluid is doubled, the pressure drop becomes Turbulent flow VmLDLDDLDDLDLfPmmmmm2.08.12.022.02.02.022.022)2(368.024)184.024Re184.02)2(−−−−−−⎟⎠⎞⎜⎝⎛====ΔVV(2VVVTheir ratio is 3.48===ΔΔ−−2.08.18.12.012)2(4092.0)2(368.0mmVPPVThe rate of heat transfer between the fluid and the walls of the channel is expressed as ln3/18.08
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This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.