Unformatted text preview: A m & V 5 2 5 10 397 . 1 /s ft 10 5683 . ft) 12 m/s)(1.25/ (7.621 Re × = × = υ = − h m D V which is greater than 10,000. Therefore, we can assume fully developed turbulent flow in the entire tube, and determine the Nusselt number from 4 . 488 ) 368 . 3 ( ) 10 397 . 1 ( 023 . Pr Re 023 . 4 . 8 . 4 4 . 8 . = × = = = k hD Nu h The heat transfer coefficient is F . Btu/h.ft 1754 ) 4 . 488 ( ft 12 / 25 . 1 F Btu/h.ft. 374 . 2 ° = ° = = Nu D k h h The heat flux on the tube is 2 4 Btu/h.ft 1070 ) ft 5960 )( ft 12 / 25 . 1 ( Btu/h 10 086 . 2 = × = = π s A Q q & & Then the surface temperature of the tube at the exit becomes F 200.6 ° = ° ° = + = ⎯→ ⎯ − = F . Btu/h.ft 1754 Btu/h.ft 1070 + F 200 ) ( 2 2 h q T T T T h q e s e s & & 822...
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This note was uploaded on 01/22/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Convection, Force, Mass, Heat

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