SOLUTNSTOPRACQUESF06

# SOLUTNSTOPRACQUESF06 - SOLUTIONS TO PRACTICE QUESTIONS FOR...

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SOLUTIONS TO PRACTICE QUESTIONS FOR THE FINAL EXAM 1. 16 x 2 ! 4 y 8 = 4 4 x 2 ! y 8 ( ) = 4 2 x ( ) 2 ! y 4 ( ) 2 ( ) = 4 2 x ! y 4 ( ) 2 x + y 4 ( ) 2. 36 a ! 4 b 10 c 2 a 2 c ! 6 " # \$ \$ % & ! 1 2 = 36 a ! 6 b 10 c 8 ( ) ! 1 2 = 36 ( ) ! 1 2 a ! 6 ( ) ! 1 2 b 10 ( ) ! 1 2 c 8 ( ) ! 1 2 = = 1 36 ( ) 1 2 a 3 b ! 5 c ! 4 = 1 36 ( a 3 b 5 c 4 = a 3 6 b 5 c 4 3. 3 x 3 x + 1 ! x x ! 2 = 3 x 3 x + 1 ( ) " x ! 2 ( ) x ! 2 ( ) ! x x ! 2 ( ) " 3 x + 1 ( ) 3 x + 1 ( ) = = 3 x x ! 2 ( ) ! x 3 x + 1 ( ) 3 x + 1 ( ) x ! 2 ( ) = 3 x 2 ! 6 x ! 3 x 2 ! x 3 x + 1 ( ) x ! 2 ( ) = ! 7 x 3 x + 1 ( ) x ! 2 ( ) 4. 2 x + 1 ( ) 3 2 ( ) 3 x ! 5 ( ) 3 ( )+ 3 x ! 5 ( ) 2 3 ( ) 2 x + 1 ( ) 2 2 ( ) = 6 2 x + 1 ( ) 3 3 x ! 5 ( )+ 3 x ! 5 ( ) 2 2 x + 1 ( ) 2 [ ] = 6 2 x + 1 ( ) 2 2 x + 1 ( ) 3 x ! 5 ( 3 x ! 5 ( ) 2 [ ] = 6 2 x + 1 ( ) 2 3 x ! 5 ( ) 2 x + 1 ( 3 x ! 5 ( ) [ ] = 6 2 x + 1 ( ) 2 3 x ! 5 ( ) 5 x ! 4 ( ) = 6 3 x ! 5 ( ) 5 x ! 4 ( ) 2 x + 1 ( ) 2 5. xy ! 1 x + y ( ) ! 1 = x y 1 x + y ( ) = x y " x + y ( ) 1 = x x + y ( ) y 6. A = P 1 + rt ( ) A = P + Pr t A ! P = Pr t A ! P Pr = Pr t Pr A ! P Pr = t t = A ! P Pr 7. 4 2 p ! 3 + 10 4 p 2 ! 9 = 1 2 p + 3 4 2 p ! 3 + 10 2 p ! 3 ( ) 2 p + 3 ( ) = 1 2 p + 3 2 p ! 3 ( ) 2 p + 3 ( ) " 4 2 p ! 3 + 10 2 p ! 3 ( ) 2 p + 3 ( ) # \$ % % & ( ( = 1 2 p + 3 # \$ % % & ( ( " 2 p ! 3 ( ) 2 p + 3 ( ) 2 p + 3 ( ) " 4 + 10 = 1 " 2 p ! 3 ( ) 4 2 p + 3 ( 10 = 2 p ! 3 ( ) 8 p + 12 + 10 = 2 p ! 3 8 p ! 2 p = ! 3 ! 12 ! 10 6 p = ! 25 p = ! 25 6 8. x + 5 x ! 5 = x + 5 ( ) x ! 5 ( ) x + 5 ( ) x + 5 ( ) = = x + 5 x + 5 x + 25 x + 5 x ! 5 x ! 25 = x + 10 x + 25 x ! 25 9. t = # of hours the other person takes to complete the job. fraction from 1 st person + fraction from 2 nd person=whole job 1 6 ! " # \$ % & job hour 4 hours + 1 t ! " # \$ % & job hour 4 hours = 1 4 ! " # \$ % & job hour 4 hours 2 3 ! " # \$ % & job + 4 t ! " # \$ % & job = 1 job 2 3 + 4 t = 1 3 t 2 3 + 4 t ! " # \$ % & = 1 3 t 2 t + 12 = 3 t 12 = t t = 12 10. y = x + 1 y 2 ! x 2 = 145 " # \$ x + 1 ( ) 2 ! x 2 = 145 x 2 + 2 x + 1 ! x 2 = 145 2 x + 1 = 145 2 x = 144 x = 72 11. let t = # hours truck has been traveling 40 t = 55 t ! 1 ( ) 40 t = 55 t ! 55 55 = 15 t t = 55 15 = 11 3 hours, so distance is 40 11 3 " # \$ % & = 440 3 miles 12. let x = # ml of the 50% solution let y = total # of ml x + 40 = y x .50 ( 40 .20 ( ) = y .25 ( ) ! " # \$ # x .50 ( 8 = x + 40 ( ) .25 ( ) .50 x + 8 = .25 x + 10 .25 x = 2 x = 8 ml B rate time distance truck car 40 55 t t - 1 40t 55(t – 1)

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13. Let h = height of original triangle then base of original triangle = h+3 New: Area of new triangle = 14 in 2 1 2 h + 3 ( ) h + 6 ( ) = 14 h + 3 ( ) h + 6 ( ) = 28 h 2 + 3 h + 6 h + 18 = 28 h 2 + 9 h ! 10 = 0 h + 10 ( ) h ! 1 ( ) = 0 h = ! 10, h = 1 Original height = 1 in .
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## This document was uploaded on 01/21/2012.

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SOLUTNSTOPRACQUESF06 - SOLUTIONS TO PRACTICE QUESTIONS FOR...

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