SOLUTNSTOPRACQUESF06

SOLUTNSTOPRACQUESF06 - SOLUTIONS TO PRACTICE QUESTIONS FOR...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
SOLUTIONS TO PRACTICE QUESTIONS FOR THE FINAL EXAM 1. 16 x 2 ! 4 y 8 = 4 4 x 2 ! y 8 ( ) = 4 2 x ( ) 2 ! y 4 ( ) 2 ( ) = 4 2 x ! y 4 ( ) 2 x + y 4 ( ) 2. 36 a ! 4 b 10 c 2 a 2 c ! 6 " # $ $ % & ! 1 2 = 36 a ! 6 b 10 c 8 ( ) ! 1 2 = 36 ( ) ! 1 2 a ! 6 ( ) ! 1 2 b 10 ( ) ! 1 2 c 8 ( ) ! 1 2 = = 1 36 ( ) 1 2 a 3 b ! 5 c ! 4 = 1 36 ( a 3 b 5 c 4 = a 3 6 b 5 c 4 3. 3 x 3 x + 1 ! x x ! 2 = 3 x 3 x + 1 ( ) " x ! 2 ( ) x ! 2 ( ) ! x x ! 2 ( ) " 3 x + 1 ( ) 3 x + 1 ( ) = = 3 x x ! 2 ( ) ! x 3 x + 1 ( ) 3 x + 1 ( ) x ! 2 ( ) = 3 x 2 ! 6 x ! 3 x 2 ! x 3 x + 1 ( ) x ! 2 ( ) = ! 7 x 3 x + 1 ( ) x ! 2 ( ) 4. 2 x + 1 ( ) 3 2 ( ) 3 x ! 5 ( ) 3 ( )+ 3 x ! 5 ( ) 2 3 ( ) 2 x + 1 ( ) 2 2 ( ) = 6 2 x + 1 ( ) 3 3 x ! 5 ( )+ 3 x ! 5 ( ) 2 2 x + 1 ( ) 2 [ ] = 6 2 x + 1 ( ) 2 2 x + 1 ( ) 3 x ! 5 ( 3 x ! 5 ( ) 2 [ ] = 6 2 x + 1 ( ) 2 3 x ! 5 ( ) 2 x + 1 ( 3 x ! 5 ( ) [ ] = 6 2 x + 1 ( ) 2 3 x ! 5 ( ) 5 x ! 4 ( ) = 6 3 x ! 5 ( ) 5 x ! 4 ( ) 2 x + 1 ( ) 2 5. xy ! 1 x + y ( ) ! 1 = x y 1 x + y ( ) = x y " x + y ( ) 1 = x x + y ( ) y 6. A = P 1 + rt ( ) A = P + Pr t A ! P = Pr t A ! P Pr = Pr t Pr A ! P Pr = t t = A ! P Pr 7. 4 2 p ! 3 + 10 4 p 2 ! 9 = 1 2 p + 3 4 2 p ! 3 + 10 2 p ! 3 ( ) 2 p + 3 ( ) = 1 2 p + 3 2 p ! 3 ( ) 2 p + 3 ( ) " 4 2 p ! 3 + 10 2 p ! 3 ( ) 2 p + 3 ( ) # $ % % & ( ( = 1 2 p + 3 # $ % % & ( ( " 2 p ! 3 ( ) 2 p + 3 ( ) 2 p + 3 ( ) " 4 + 10 = 1 " 2 p ! 3 ( ) 4 2 p + 3 ( 10 = 2 p ! 3 ( ) 8 p + 12 + 10 = 2 p ! 3 8 p ! 2 p = ! 3 ! 12 ! 10 6 p = ! 25 p = ! 25 6 8. x + 5 x ! 5 = x + 5 ( ) x ! 5 ( ) x + 5 ( ) x + 5 ( ) = = x + 5 x + 5 x + 25 x + 5 x ! 5 x ! 25 = x + 10 x + 25 x ! 25 9. t = # of hours the other person takes to complete the job. fraction from 1 st person + fraction from 2 nd person=whole job 1 6 ! " # $ % & job hour 4 hours + 1 t ! " # $ % & job hour 4 hours = 1 4 ! " # $ % & job hour 4 hours 2 3 ! " # $ % & job + 4 t ! " # $ % & job = 1 job 2 3 + 4 t = 1 3 t 2 3 + 4 t ! " # $ % & = 1 3 t 2 t + 12 = 3 t 12 = t t = 12 10. y = x + 1 y 2 ! x 2 = 145 " # $ x + 1 ( ) 2 ! x 2 = 145 x 2 + 2 x + 1 ! x 2 = 145 2 x + 1 = 145 2 x = 144 x = 72 11. let t = # hours truck has been traveling 40 t = 55 t ! 1 ( ) 40 t = 55 t ! 55 55 = 15 t t = 55 15 = 11 3 hours, so distance is 40 11 3 " # $ % & = 440 3 miles 12. let x = # ml of the 50% solution let y = total # of ml x + 40 = y x .50 ( 40 .20 ( ) = y .25 ( ) ! " # $ # x .50 ( 8 = x + 40 ( ) .25 ( ) .50 x + 8 = .25 x + 10 .25 x = 2 x = 8 ml B rate time distance truck car 40 55 t t - 1 40t 55(t – 1)
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
13. Let h = height of original triangle then base of original triangle = h+3 New: Area of new triangle = 14 in 2 1 2 h + 3 ( ) h + 6 ( ) = 14 h + 3 ( ) h + 6 ( ) = 28 h 2 + 3 h + 6 h + 18 = 28 h 2 + 9 h ! 10 = 0 h + 10 ( ) h ! 1 ( ) = 0 h = ! 10, h = 1 Original height = 1 in .
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 9

SOLUTNSTOPRACQUESF06 - SOLUTIONS TO PRACTICE QUESTIONS FOR...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online