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PAGE #5 - D500t500 t600 = D600 fA.15 x 10-14m2 /5 '\10 h) =

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21 *' 5. (a) We are asked to calculate the diffusion coefficient for Cu in AI at 500°C. Using the data in Table 5.2 D = Doexpl-~ ) [ 136000 J/mol ] -5 2 , = (6.SX10 m /S}XP -(8.31 J/mol-K)(SOO +273 K) -14 2 = 4.15 x 10 m /5 (b) This portion of the problem calls for the time required at 600°C to produce the same diffusion result as for 10 h at 500°C. Equation (5.7) is employed as D500t500 = D600t600 Now, from Equation (5.8) -5 2 \. [ 136,000 J/mOI ] D600 = ~.5X10 m /5J'XP -(8.31 J/mol-K)(600+273K) -13 2 = 4.69 x 10 m Is Thus,
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Unformatted text preview: D500t500 t600 = D600 fA.15 x 10-14m2 /5 '\10 h) = ~.,""' 1\,1 1II "'}'\,1"1= 0.88h (4.69 x 10-13 m2 /5 ) :I*: 6. This problem calls for us to make a stress-strain plot for a magnesium specimen, given its tensile load-Iength data, and then to determine some of its mechanical characteristics. (a) The data are plotted below on two plots: the first corresponds to the entire stress-strain curve, while for the second, the curve extends just beyond the elastic region of deformation. F...
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This note was uploaded on 01/22/2012 for the course ME 2733 taught by Professor Meng during the Fall '10 term at LSU.

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