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Unformatted text preview: Then you can easily sketch the root locus of (7). It is shown in Figure 2. 4) part c): 10 2 ) ( ) 10 )( ( ) ( 1 = + + + + + + = s K s s s s s s T ⇔ 10 2 11 11 1 1 1 2 3 2 = + + + + + K s K s s s s (8) Let 2 1 = K , (8) is written as 20 4 11 11 1 2 3 2 = + + + + + s s s s s (9) Then you can easily sketch the root locus of (9). It is shown in Figure 3. Figure 2: Root Locus of 511b Figure 1: Root Locus of 511a Figure 3: Root Locus of 511c...
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This note was uploaded on 01/23/2012 for the course EE 4580 taught by Professor Gu during the Fall '10 term at LSU.
 Fall '10
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