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Unformatted text preview: Outcome Disease No Disease Totals Group Placebo S 1 n 1-S 1 n 1 Drug Treatment S 2 n 2-S 2 n 2 If we were constructing a 95% condence interval for = 1 / 2 , show that the standard error SE(log( 1 / 2 )) = r 1 S 1 + 1 n 1-S 1 + 1 S 2 + 1 n 2-S 2 , is equivalent to the standard error obtained using the formula on page 541. No problems to do in R (unless you use R for the pencil and paper problems) Include all relevant R input and output. Describe the output in your own words. You may nd the code included in the lab exercises useful....
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- Fall '08