# shmwk06 - Vin x − Fx = ρ QV)out − ρ QV)in = ρ...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Vin x − Fx = ( ρ QV )out − ( ρ QV )in = ρ Q (Voutx − Vinx ) x x ( ρ Q )out = ( ρ Q )in x VinVinxVout Vin ( − cosθ ) θ = 30° − cosθ x 1/2 1/2 Fx (π D 2 / 4 ) 1200 N (π / 4 )( 0.04 m )2 Fx = ρ QVin (1 + cosθ ) = Q= = 3 3 Ain ρ (1 + cosθ ) 10 kg/m (1 + cos30° ) 3 = 0.028 m /s Dy − ( F ' ) x = ( ρ Q 'V ' )out − ( ρ Q 'V ' )in = ρ Q (V ' )outx − (V ' )inx ρ Q 2 (1 + cosθ ) x x Q ' V ' F ' 2 ( F ' ) x = ρ Q ' (V ' )in (1 + cosθ ) = ρ (V ' )in Ain (1 + cosθ ) 1/2 1/2 ( F ')x 1800 N V ' )in = = 27.7 m/s = 3 ( 2 2 3 ρ (1 + cosθ ) (π D / 4) 10 kg/m (1 + cos30°)(π / 4 )( 0.04 m ) Q / Ain = Q / (π D 2 / 4 ) = (V ' )in = Vin − Vvane Vvane = Vin − (V ' )in = (22.6 − 27.7) m/s = −5.1 m/s x • • p V2 p p V2 p V2 Q2 = + z − + z = Δ = +z+ = +z+ γ 2 g 1 γ 2 g 2 2 g 1 2 gA12 γ γ 2 1 V2 Δ p 2 − p a = −γ ( z 2 − z a ) p p Q2 pa − pb ≈ 0 Δ = + z − + z = za − zb = h = 2 gA12 γ 2 γ 1 pb − p1 = −γ ( zb − z1 ) Δ = (γ m / γ ) − 1 h A = π Dh FA,z, FA,z = 3.52 kN xx x − Rx + ( pA )in − ( pA )out = ( ρ QV )out − ( ρ QV )in x x Rx = ( pA )in − ( pA)out + ( ρ QV )in − ( ρ QV )out x x x x = (γ H 2 / 2 ) − (γ h 2 / 2 ) + ρ Q ( Q / H ) − ( Q / h ) Q = VinH hs hp p p V2 V2 + z +α + hp = + z + α + hL 2 g in 2 g out γ γ pin = 0 = Vin = Vout h p = Wpump / ( mg ) = W pump / (γ Q ) = 3 hp/ ( 62.4 lbf/ft 3 ) (100 gpm) = 118.7 ft p 2 atm hL = hp + zin − zout − out = 118.7 ft − 20 ft − = 30.9 ft γ 62.4 lbf/ft 3 h p ≥ 0 pout hL = −3.1 ft pout = 3 atm y R y x x R ) QV (ρ p =0 θ − Ry + [( pA)in ] y + [ ( pA)out ] y = ( ρ QV )out − ( ρ QV )in = ρ Q (Vout ) y − (Vin ) y y y (ρQV) ( ρ Q )in = ( ρ Q )out pout = 0 y out out in (Vout ) y = ( Q / Aout )( − sinθ ) Q Ry + ρ Q − sinθ − Vin Aout = 189.6 lbf/ft 2 pin = Ain (pA)in x p p V2 V2 + z +α = + z +α + hL 2 g in γ 2 g out γ pout 2 p V 2 − Vout hL = in + in = 2.36 ft γ 2g ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online