This preview shows pages 1–5. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: = dP dy d2udy2dy dx = d2udy2 1dPdx = + dudy 1dPdx y C1 = + + u 12dPdx y2 C1y C2 C1 and C2 could be obtained from the boundary conditions: 1) No slip at lower wall U(y=0) = 0 C2 = 0 2) No Slip at top wall U (y = l) = 0 C1 = 121dPdx l Therefore: = + u 12dPdx y2 12dPdx l y Maximum velocity occurs in the center at y = l/2 = ==.*  . = . / uy l2 18dPdxl2 1811 12E 3Pa s 0 06Pa1m1cm21m100cm2 0 00067m s Problem 5 (10 points) Drag on a flat plat could be found from Eq 18.22 = . = . . * * . = . Cf 1 328Re 1 3281 23 1 11 79E 5 0 005 = = . Drag 12Cf V2 A 0 015N Since the plate has 2 faces = * = . Net Drag 2 Plate Drag 0 03 N Boundary layer thickness could be calculated using Eq. 18.23 = 5xRe Problem 6 (5 points) Following steps in problem 5 yields: = . Cf 0 0014 = . Drag 3 5 N = . Net Drag 7 03N Boundary Layer thickness Decreases but the drag increase....
View
Full
Document
This document was uploaded on 01/22/2012.
 Fall '09

Click to edit the document details