Physics ..

Physics .. - B heavy = 500Vg> upward direction Another...

This preview shows pages 1–2. Sign up to view the full content.

A tank holds two different liquids: a heavy one on the bottom with a density of 1 g/cc and a lighter one above it with a density of 0.6 g/cc. A sphere is immersed in the tank and is seen to rest in equilibrium with exactly half of it in the dense fluid and half in the light. What is the density of the sphere? Let the density of the ball be d and volume be V. Density of the Heavy fluid is 1 g/cc = 1000 kg/m 3 Density of the lighter fluid is 0.6 g/cc = 600 kg/m 3 Half of the ball is immersed in the heavy liquid and hence the force of buoyancy is equal to B heavy = density of the heavy fluid * Volume immersed * acceleration due to gravity B heavy = 1000 kg/m 3 * (V/2)*g ------ > upward direction

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: B heavy = 500Vg ------ > upward direction Another half of the ball is immersed in the lighter liquid and hence the force of buoyancy is equal to B light = density of the lighter fluid * Volume immersed * acceleration due to gravity B light = 600 kg/m 3 * (V/2)*g ------- > upward direction B light = 300Vg ------- > upward direction The weight of the ball is in the downward direction and let it be W. W=mg Mass=Volume*density => m=Vd W=Vdg As ball is in equilibrium downward forces and upward forces should be equal. B heavy + B light = W 500Vg + 300Vg = Vdg d = 800 kg/m 3 d = 0.8 gm/cm 3 Density of the ball = 0.8 g/cc...
View Full Document

{[ snackBarMessage ]}

Page1 / 2

Physics .. - B heavy = 500Vg> upward direction Another...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online