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# C1993 - 1993 Physics C Solutions Distribution of Points...

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Unformatted text preview: 1993 Physics C Solutions Distribution of Points Mech l. (a) 3 points Using the expression for the energy stored in a spring: U - % kxz 1 point Substituting: :1 - :32: [400 E} (0.5 m)2 1 point m U - 50 J 1 point (b) 5 points For recognition of conservation of energy or work-energy theorem 1 poine Kinetic energy of block C: K w % mcvcz 1 pain: Work done (or energy dissipated by) friction: Wf — pFnd l paint K -‘ U -- Wf 1 2 d l . E mCUC - U w pmcg poxnt Solving for v3: v /_3 (U m m d) C - mC “ C3 Substituting: vc .. /“"‘42kg (50 J —— (0.4)(4 kg)(10 m/s2)(o.5 m)) ”C - 4.58 m/s 1 point (Full credit else awarded for correct alternate solution computing anet dx, where Fnet - kx - pFn, to find the kinetic energy, and then computing the speed.) 1993 Physics C Solutions . Distribution ' of Points Mach 1. (continued) (0) 3 points For any statement of conservation of momentum 1 point mCUC - (mg + mD)vf 1 point Solving for vf: vf ' move/(mt + mo) Substituting: of - (4 kg)(4.58 m/s)/(A kg + 2 kg) 1 point Uf u 3.05 m/s (d) 3 points The blocks come to rest when all their kinetic energy 1 point has been dissipated, i.e, AXE a Work done by frictional force %(mc + mD)vf2 w ”(“0 + mD)gd 1 point Solving for d: d w vfz/Zug Substituting: d a (3.05 m/s)2/(2)(o.4)(1o m/sz) d a 1.16 m 1 point (Alternate Solution) \ (Alternate Points) 2? a ma (1 point) 2F #(mc + mn>g a - E“ - "YEE~1_EB7wM“ u pg a (0.4)(10 m/sz) u 4 m/s2 v2 a v02 + Zad (or other appropriate kinematic equations) (1 point) v2 “ v92 0 — (3 05 m s)2 d-T-mjL—‘l.16m ‘ (1 point) UNITS: For correct units on all answers 1 point ...
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C1993 - 1993 Physics C Solutions Distribution of Points...

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