hw8sol - ISyE 2027 Fall 2011 Hmwk 8 Solution 1(a Binomial...

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Unformatted text preview: ISyE 2027 Fall 2011 Hmwk 8 Solution November 17, 2011 1. (a) Binomial with parameter ( 5, 1 4 ) ; (b) 5 4 ; (c) 15 16 ; (d) ( 5 i ) ( 1 4 ) i ( 5- i j ) ( 1 2 ) j . (e) mean 5, variance 0. 2. P (- k 6 Z 6 k ) = 0.682 if k = 1, 0.956 if k = 2 0.997 if k = 3 3. (a) 0.682, (b) 0.956, (c) 0.997, (d) 0.022, (e) 0.021, (f) 0.044. 4. (a) 0.975, (b) 0.05, (c) 0.2195, (d) 0.2195. (e) 1. 5. Let Z be a standard normal random variable. I would not expect the nor- mal approximation to be great since X is discrete, rather skewed (asym- metric), and the sample size is not particularly large. (a) P { Y 6 3.5 } , P { Y 6 2.5 } , P { 2.5 < Y 6 3.5 } , P { 2.5 < Y 6 4.5 } . (b) P { X 6 3 } = 3 X k = P { X = k } = 3 X k = 15 k ( 1 / 5 ) k ( 4 / 5 ) 15- k ≈ 0.6482 P { Y 6 3.5 } = P Y- 3 2 √ 15 / 5 6 3.5- 3 2 √ 15 / 5 = P { Z 6 √ 15 / 12 } ≈ .6266 P { X < 3 } = 2 X k = P { X = k } = 2 X k = 15 k ( 1 / 5 ) k ( 4 / 5 ) 15- k ≈ 0.3980 1 P { Y 6 2.5 } = P Y- 3 2 √ 15 / 5 6 2.5-...
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This note was uploaded on 01/22/2012 for the course ISYE 2027 taught by Professor Zahrn during the Fall '08 term at Georgia Tech.

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hw8sol - ISyE 2027 Fall 2011 Hmwk 8 Solution 1(a Binomial...

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