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mdm12Section2_6_OddSolutionsFinal

# mdm12Section2_6_OddSolutionsFinal - Q1-5 Q9 Q19 Q7 Q11-17...

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Q1-5 Q7 Q9 Q11-17 Q19 CHAPTER 2 Section 2.6, p. 148–150 Solutions to Odd Number Problems 1. a) x ( x -mean) 2 b) x ( x -mean) 2 5 4.2539 12.55 221.2200 7 0.0039 15.31 146.7300 9 3.7539 21.98 29.6300 6 1.1289 45.35 321.3700 5 4.2539 19.81 57.9630 10 8.6289 33.89 41.8180 8 0.8789 29.53 4.4380 2 25.6290 30.19 7.6544 11 15.5040 38.20 116.1400 8 0.8789 7 0.0039 7 0.0039 6 1.1289 9 3.7539 5 4.2539 8 0.8789 a) sum( ) mean = 16 113 = 16 =7.1 x ( ) _ 2 sum( ) variance = 16 1 = 5.0 x x standard deviation = 5.0 2.2 =

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b) mum( ) mean = 9 246.81 = 9 = \$27.42 x ( ) _ 2 sum( ) variance = 9 1 = \$118.37 x x standard deviation = 118.37 \$10.88 = 3. first quartile: x < 67 second quartile: 67 x < 88 third quartile: 88 x < 105 fourth quartile: x 105 a) first quartile b) second quartile c) third quartile 5. mean, x = 20; standard deviation, s = 4.06. x -score z -score = - x x s 18 –0.49 15 –1.23 26 1.48 20 0.00 21 0.25 Top
7. Hours Per Week, x Number of Employees, f fx f ( x – mean) 2 12 1 12 566.81 32 5 160 72.493 35 7 245 4.5666 38 8 304 38.45 42 5 210 191.72 sum = 26 sum = 931 sum = 874.03846 Nurses are considered as a sample: 931 mean 26 35.8 = = ( ) 874.03846 sample variance 26 1 35.0 = = sample standard deviation 35.0 5.9 = = Nurses are considered as a population: variance = 33.6 standard deviation = 5.8 b) Since there are 26 data, the median is the average of the 13th and 14th data.

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