mdm12Section4_1_OddSolutionsFinal

# mdm12Section4_1_OddSolutionsFinal - Q1-3 Q7-17 Q5 Q19-23...

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Unformatted text preview: Q1-3 Q7-17 Q5 Q19-23 CHAPTER 4 Section 4.1 pp. 229–231 Solutions to Odd Number Problems 1. There are 2 × 3 × 2 = 12 different sandwiches possible. 3. There are 4 6s and 12 face cards in a deck of 52. n = 4 + 12 = 16 Top 5. a) (2)(3)(2) = 12 b) (3)(2)(1) = 6 c) (3)(3) = 9 Top 7. a) b) (3)(4)(2) = 24 9. n =(5)(3) = 15 A buyer would have a choice of each kind of material in one of five different colours. 11. n = (6 +1)(3 +1) = 28 13. a) n(Canada) = (26 x 10)3 = 17 576 000 n(USA) = 105 =100 000 b) 17 576 000 − 100 000 = 17 476 000 15. n = (3)(2)(2) = 12 17. a) n = 10(9) = 90 b) n = (8)(7) = 56 Top 19. n(no restrictions) = 5! = 120 n(t and h together) = 2 × 4! =48 n(t and h apart) = 120 − 48 = 72 21. Solutions for the Achievement Checks are in the Teacher Resource. 23. Count the possibilities for every digit of the 5-digit number. Numerals can be repeated, but the first digit cannot be a zero. n(no digit 8 but may or may not include 5) = (8)(9)(9)(9)(9) = 52 488 n(neither an 8 nor a 5) = (7)(8)(8)(8)(8) =28 672 n(no digit 8 but include 5) = 52 488 − 28 672 = 23 816 25. a) The possible positions reached after one move are marked by X. The possible positions reached after two moves are marked by Y. The possible positions reached after three moves are marked by Z. Z Z Z Z YZ Y Z ZY Z Y Z Z Y Y Z Z Y Y X Z Z YZ X Z Y Z Z i) n(one move) = 2 Z Z Z Z ii) n(two moves) = 10 iii) n(three moves) = 22 b) No; the number of subsequent moves depends on the previous move. Top ...
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mdm12Section4_1_OddSolutionsFinal - Q1-3 Q7-17 Q5 Q19-23...

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