mdm12Section4_2_OddSolutionsFinal

mdm12Section4_2_OddSolutionsFinal - Q1-17 Q19-23 CHAPTER 4...

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Q1-17 Q19-23 CHAPTER 4 Section 4.2, pp. 239–240 Solutions to Odd Number Problems 1. a) 6! b) 8! c) 3! d) 9! 3. a) 6 P 3 b) 9 P 4 c) 20 P 4 d) 101 P e) 76 P 7 5. a) 5040 b) 43 680 c) 20 d) 3024 e) 5040 7. a) 12! b) 72x7! = 9 8 × 7! × = 9! c) ( n +4)( n +5)( n +3)! = ( n +5)! 9. a) n (no restrictions) = 7! = 5040 b) n (Brenda in the middle) = (1)(6!) = 720 c) n (Ahmed far left and Yen far right) = 1 × 1 × 5! = 120 d) n (Hanh and Brian together) = 2 × 6! = 1440 11. Consider the captain and assistant captain as one object, which can be arranged in two ways. n = 2 × 11! = 79 833 600 13. Joanne likes 12 of Charlene's CDs. n = 12! = 479 001 600 15. a) 52 P 5 = 311 875 200 b) 52 P 10 = 5.74 10 × 16 c) 26 P 5 = 7 893 600 d) 4 P 4 = 24 17. n = 12! = 479 001 600
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This note was uploaded on 01/23/2012 for the course MATHS MDM-01 taught by Professor Mr.m during the Spring '10 term at Seneca.

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mdm12Section4_2_OddSolutionsFinal - Q1-17 Q19-23 CHAPTER 4...

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