mdm12Section4_5_OddSolutionsFinal

mdm12Section4_5_OddSolutionsFinal - Q1-5 Q9 Q13-17 Q7 Q11...

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Q1-5 Q7 Q9 Q11 Q13-17 Q19 CHAPTER 4 Section 4.5, pp. 256–259 Solutions to Odd Number Problems 1. a b 495 d e f 825 3003 2112 h 495 + d = 825 d = 330 f + 825 = 2112 f = 1287 b + 495 = 1287 b = 792 e + 1287 = 3003 e = 1716 a + 792 = 1716 a = 924 h = 3003 + 2112 = 5115 924 792 495 330 1716 1287 825 3003 2112 5115 3. To find entries in the next row, add the term immediately above to the term immediately above and left, e.g., 136 = 120 + 16. To find entries in the previous row, subtract the term immediately left from the term immediately below, e.g., 105 = 120 15. 1 15 105 455 1365 3003 5005 6435 6435 1 16 120 560 1820 4368 800811 44012 870 1 17 136 680 2380 618812 37619 44824 310 5. 8! 3!5! 56 n = = Top
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7. a) There are 6 + 12 + 10 + 5 = 33 paths to reach the top row. 6 12 10 5 6 6 4 1 3 x 3 1 3 3 x 1 2 1 1 1 o b) There are 56 + 95 + 101 + 98 + 72 + 45 + 18 + 5 = 490 paths to reach the top row. 56 95 101 98 72 45 18 5 25 31 39 31 28 13 4 1 9 16 x 16 9 3 1 3 6 7 6 3 x 1 2 3 2 1 1 1 1 o Top
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9. a) 4 b) 4 c) 12 d) 16 e) Yes; if the direction were reversed, each route could be retraced. Therefore, the number of routes would be the same. Top
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11. Slot 3 or 4 provides the highest probability, 5/16, of getting to the $5000 slot.
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This note was uploaded on 01/23/2012 for the course MATHS MDM-01 taught by Professor Mr.m during the Spring '10 term at Seneca.

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mdm12Section4_5_OddSolutionsFinal - Q1-5 Q9 Q13-17 Q7 Q11...

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