mdm12Section5_T_OddSolutionsFinal

# mdm12Section5_T_OddSolutionsFinal - Q1-5 Q7-13 CHAPTER 5...

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Q1-5 Q7-13 CHAPTER 5 Chapter Test, pp. 298–299 Solutions to Odd Number Problems 1. a) 25 25 25! 25!0! 1 C = = b) 52 1 52! 1!51! 52 C = = c) 12 3 12! 3!9! (12)(11)(10) 3! 220 C = = = d) 40 15 10 40! 15!25! 4.0225 345 06 10 C = 3. a) (3 x – 4) 4 = (3 x ) 4 + 4(3 x ) 3 (–4) + 6(3 x ) 2 (–4) 2 + 4(3 x )(–4) 3 + (–4) 4 = 81 x 4 – 432 x 3 + 864 x 2 – 768 x + 256 b) (2 x + 3 y ) 7 = (2 x ) 7 + 7(2 x ) 6 (3 y ) + 21(2 x ) 5 (3 y ) 2 + 35(2 x ) 4 (3 y ) 3 + 35(2 x ) 3 (3 y ) 4 + 21(3 x ) 2 (3 y ) 5 + 7(2 x )(3 y ) 6 + (3 y ) 7 = 128 x 7 + 1344 x 6 y + 6048 x 5 y 2 + 15 120 x 4 y 3 + 22 680 x 3 y 4 + 20 412 x 2 y 5 + 10 206 xy 6 + 2187 y 7 5. a) 14 C 4 = 1001 b) 7 C 4 = 35 c) 7 C 2 7 × C 2 = (21) 2 = 441 d) 14 C 4 7 C 4 = 1001 – 35 = 966 Top

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7. a) 19 + 8 + 13 + 24 + 1 + 29 + 24 = 118 b) 1 9. a) Each item can either be selected or not selected. Assuming that at least one item is chosen, the number of different combinations is (2 2 )(2 4 )(2 3 )(2 3 )(2 3 ) – 1 = 2
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## This note was uploaded on 01/23/2012 for the course MATHS MDM-01 taught by Professor Mr.m during the Spring '10 term at Seneca.

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mdm12Section5_T_OddSolutionsFinal - Q1-5 Q7-13 CHAPTER 5...

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