mdm12Section6_3_OddSolutionsFinal

# mdm12Section6_3_OddSolutionsFinal - Q1-7 Q9-15 CHAPTER 6...

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Q1-7 Q9-15 CHAPTER 6 Section 6.3, pp. 324–326 Solutions to Odd Number Problems 1. The three possible scenarios are F 1 F 2 versus M 1 M 2 , F 1 M 1 versus F 2 M 2 , and F 1 M 2 versus F 2 M 1 P (two females are partners) = 1 3 3. a ) b ) 52 30 82 (2R) 10 28 5 14 CC P C × = = = 50 3 2 (not 2G) 1 3 1 28 25 28 P C × =− = 5. a) b) 83 18 3 (all runners) 56 816 7 102 C P C = = = 61 41 81 18 3 (one of each) 192 816 4 17 CCC P C × × = = = 7. a) If she draws her own name, it does not count. There are just 8 permissible draws. 22 (2 sisters excluding herself) 1 28 C P C = = b) 11 (main to middle, fun to eldest) 1 56 P P × = = Top

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9. a) 84 20 4 (four wingers) 70 4845 14 969 C P C = = = b) 14 4 20 4 (no goalies or centres) 1001 4845 C P C = = 11. 11 41 11 31 92 (Suki and Leo are on the team) 43 36 7 36 CCCC P C × = + = = 13. Solutions for the Achievement Checks are in the Teacher Resource.
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## This note was uploaded on 01/23/2012 for the course MATHS MDM-01 taught by Professor Mr.m during the Spring '10 term at Seneca.

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mdm12Section6_3_OddSolutionsFinal - Q1-7 Q9-15 CHAPTER 6...

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