HW17%20solution

# HW17%20solution - ECE 201 Spring 2010 Homework 17 Solutions...

This preview shows pages 1–3. Sign up to view the full content.

ECE 201 Spring 2010 Homework 17 Solutions Problem 27 (a) Let V be the common voltage across C 1 and C 2 . Thus ( C 1 + C 2 ) dV dt = i s ( t ) C 2 dV dt = i C 2 ( t ) i C 2 ( t )= C 2 C 1 + C 2 i s ( t ) (b) Using KVL across the second loop and relation from part (a), we get r m i C 2 ( t ) - ( L 1 + L 2 ) di dt =0 v out ( t )= L 2 di dt = r m L 2 C 2 ( L 1 + L 2 )( C 1 + C 2 ) i s ( t ) Problem 38 (a) Starting from the right end and combining the inductors in series and parallel consecutively, we get L eq as L eq = 4 + ((36) || (10 + ((1 + 5) || (3)))) = 4 + ((36) || (10 + ((6) || (3)))) 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
= 4 + ((36) || (10 + (2))) = 4 + ((36) || (12)) = 4 + 9 = 13 mH (b) Clearly, the given circuit has 1.2 mH and 0.6 mH in parallel, and this com- bination is in series with 2.4 mH, the equivalent of which is in parallel with 7 mH. Thus L eq =7 || (2 . 4 + (1 . 2 || 0 . 6)) =7 || (2 . 4 + 0
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 01/22/2012 for the course ECE 201 taught by Professor All during the Spring '08 term at Purdue University-West Lafayette.

### Page1 / 3

HW17%20solution - ECE 201 Spring 2010 Homework 17 Solutions...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online