problem02_82 solution

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.82: a)

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b) From the speed found in part (c), the maximum height is . m 635 ) s m 80 . 9 ( 2 ) s m 6 . 111 ( 2 2 = c) After the fuel is burned, the rocket has speed (40.0 2 s m )(2.50 s) = 100 m/s and has reached a height ( 2 1 )(40.0 2 s m )(2.50 s) 2 = 125 m. The speed of the rocket just before it hits the ground is then , s m 6 . 111 ) m 125 )( s m 80 . 9 ( 2 ) s m 100
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Unformatted text preview: ( ) ( 2 2 2 2 =--=--= y y g v v or s m 112 to three significant figures. d) The time from launch to the highest point is not the same as the time from the highest point back to the ground due to the upward acceleration of the engine in the first 2.5 s....
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• Highest point, 100 metres

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