2_1_Lecture 14

2_1_Lecture 14 - EE 2 Fall 2007 Class 14 slides 1 Outline...

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1 EE 2 Fall 2007 Class 14 slides
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2 Outline Review of last class on p-n junction: E E c
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3 Consider the two neutral regions in an abrupt p-n junction. In the neutral p-region p= p p0 = N A - Electrostatic potential is φ p = - kT ln(p p0 /n i ) = kT ln(N A /n i )
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4 In the neutral n-region n= n n0 = N D Electrostatic potential is φ n = + kT ln(n n0 /n i ) = kT ln(N D /n i )
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9 p-n junction: potential variation We will now consider the potential variation in the space charge region. As seen in the last slide the electrostatic potential remained constant in the neutral p-region and in the neutral n-region and the electric field which is the gradient of the electrostatic potential was zero in the two neutral regions. However, there is a space charge region on either side of the metallurgical junction at x = 0, the origin in the x-axis. The space charge region on the p-side (i.e., to the left of x = 0) is due to ionized acceptor atoms and has a charge density equal to ρ = - q N A
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2_1_Lecture 14 - EE 2 Fall 2007 Class 14 slides 1 Outline...

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