problem02_84 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.84: a) In 3.0 seconds the teacher falls a distance m 1 . 44 ) s 0 . 9 )( s m 8 . 9 ( 2 1 2 1 2 2 2 = = = gt y To reach her ears after 3.0 s, the sound must therefore have traveled a total distance of m 1 . 44 2 m ) 1 . 44 ( - = - + h h h ,where h is the height of the cliff. Given 340 m/s for the speed of sound: m 1020 s) 0 3 )( s m (340 m 1 . 44 2 = = - .
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Unformatted text preview: m 530 or m 532 = h to the given precision. b) We can use ) ( 2 2 2 y y g v v y y-+ = to find the teacher's final velocity. This gives 2 2 2 2 s m 10427 m) 532 )( s m 8 . 9 ( 2 = = y v and s m 102 = y v ....
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• Speed of sound, Velocity, Total Distance

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