{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework _8 Spring 11

# Homework _8 Spring 11 - BME6360 Neural Engineering...

This preview shows pages 1–2. Sign up to view the full content.

BME6360 Homework #8 Spring 2011 Neural Engineering Prof. Wheeler This is a demonstration assignment. It's purpose is to review some basic operations with Fourier transforms. It's primary goal is to help you look at a Fourier transform, especially one done with the Fast Fourier Transform (e.g. discrete time, discrete frequencies), and to interpret it. Some of the functions used here will be used on Homework #9. The following program files are available under: ifftplot.m, fftplot.m, ftp.m, xcorcirc.m, hw8data.mat The following vectors are available in hw8data.mat and may be loaded by executing load hw8data F1a, F1b, F1c, F1d, F1e, F1f, F1g, F1h -- Frequency domain values for problem 1. F2a, F2b, F2c, F2d -- Frequency domain values for problem 2. s1, c1, s2, c32, c31, c33, mix, c6401, c3_5, s16_3, czeros -- time domain values for problem 3 y4a, pt1, pt2 -- time domain values for problem 4 Rpt1, Rpt2 -- autocorrelations for problem 4 t5, y5, y5n -- time domain values for problem 5 You do not need to execute the instructions below which create the vectors. They are repeated here to remind you as to their content. 1. In order to understand FFTs and power spectra, you should understand that each element of an FFT of a signal represents a complex exponential. This problem demonstrates that correspondence by using the inverse transform to reconstruct the time domain signal of single frequency domain elements. Using the function ifftplot demonstrate the correspondence between the following sequences in the frequency domain and their time domain: a. F1a=16*[1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]' ; % should be DC (constant) b. F1b=16*[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0]' ; % exp(jwt); one cycle % the result should have both real and imaginary components c. F1c=16*[0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0] '; % exp(j2wt); two cycles d. F1d=16*[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1] '; % exp(-jwt); one cycle; why? e. F1e=16*[0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0] '; % exp(-j2wt); two cycles f. F1f=16*[0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0]'; % max frequency g. F1g=16*[0 -j 0 0 0 0 0 0 0 0 0 0 0 0 0 0].'; % (-j)*exp(jwt); one cycle; real part is sin(wt) h. F1h=16*[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 j].'; % (j)*exp(-jwt); one cycle; real part is sin(wt) NOTES: We assume that all signals are column vectors, not row vectors.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern