230_Sp10_L32_post - CHEM 230 Sp10 Lecture 32 Chapter 13:...

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Unformatted text preview: CHEM 230 Sp10 Lecture 32 Chapter 13: Chemical Kinetics 1) Mechanistic Overall Rate Law 2) Equilibrium 3) Molecularity Session ID: 230 Which step is rate determining? Overall : 2O 3(g) 3O 2(g) Mechanism: O 3(g) O 2(g) + O (g) Rate = k 1 [O 3 ] slow O 3(g) + O (g) 2 O 2(g) Rate = k 2 [O 3 ][O] fast Overall rate = k 1 [O 3 ] first order in O 3 Mechanism: O 3(g) O 2(g) + O (g) Rate = k 1 [O 3 ] ! fast O 3(g) + O (g) 2 O 2(g) Rate = k 2 [O 3 ][O] slow rate = k 2 [O 3 ][O] rate = k 2 [O 3 ]k 1 [O 3 ]= k 2 k 1 [O 3 ] 2 =k[O 3 ] 2 second order in O 3 sub in for intermediates as much as possible (OK to have H + and OH- in Which step is rate determining? Overall : 2O 3(g) 3O 2(g) Mechanism: O 3(g) O 2(g) + O (g) Rate = k 1 [O 3 ] slow O 3(g) + O (g) 2 O 2(g) Rate = k 2 [O 3 ][O] fast Overall rate = k 1 [O 3 ] first order in O 3 Mechanism: O 3(g) O 2(g) + O (g) Rate = k 1 [O 3 ] ! fast O 3(g) + O (g) 2 O 2(g) Rate = k 2 [O 3 ][O] slow rate = k 2 [O 3 ][O] rate = k 2 [O 3 ]k 1 [O 3 ]= k 2 k 1 [O 3 ] 2 =k[O 3 ] 2 second order in O 3 sub in for intermediates as much as possible (OK to have H + and OH- in aqueous solutions) Magnitude of k Reaction steps are often designated "fast" or "slow" based on the rate constant ( k ) for the step: large k is fast, small k is slow 2H 2(g) + 2 NO (g) N 2(g) + 2H 2 O (g) rate = k[H 2 ][NO] 2 Mechanism I 1) H 2 + NO H 2 O + N 2) N + NO N 2 + O 3) O + H 2 H 2 O Which step is rate determining? Step 1 Rate = k 1 [H 2 ][NO] Step 2 Rate = k 2 [N][NO] =k 2 k 1 [H 2 ][NO][NO] Mechanism II 1) H 2 + 2NO N 2 O + H 2 O 2) N 2 O + H 2 N 2 + H 2 O Step 1 Rate = k 1 [H 2 ][NO] 2 Concept Question The reaction 2 A + B C has the rate law k [A][B] . ....
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This note was uploaded on 01/24/2012 for the course PCHEM 230 taught by Professor Gottfried during the Fall '11 term at University of Michigan.

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230_Sp10_L32_post - CHEM 230 Sp10 Lecture 32 Chapter 13:...

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