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Homework 8 - else getNodeAt(position-1.setNextNode(newNode...

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//Page 177 #9 //a. First in the chain public void addToFront(T newEntry){ DNode newNode = new DNode( null , newEntry, firstNode); if (isEmpty()) lastNode = newNode; else firstNode.setPreviousNode(newNode); firstNode = newNode; } // end addToFront //b. Last in the chain public void addToBack(T newEntry) { DNode newNode = new DNode(lastNode, newEntry, null ); if (isEmpty()) firstNode = newNode; else lastNode.setNextNode(newNode); lastNode = newNode; } //c. Between existing nodes in the chain. public void addToBetween(T newEntry, int position) { DNode newNode = new DNode(getNodeAt(position-1), newEntry, getNodeAt(position)); if (isEmpty()) firstNode = newNode;
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Unformatted text preview: else { getNodeAt(position-1).setNextNode(newNode); getNodeAt(position).setPreviousNode(newNode); } } //Page 198 #7 // a) Remove First public T removeFirst (){ T first = null ; if (!isEmpty ()) { first = firstNode.getData (); firstNode = firstNode.next; if (firstNode == null ) lastNode = null ; else firstNode.setPreviousNode ( null ); } return first; } // b) Remove Last public T removeLast() { T last = null ; if (!isEmpty ()) { last = lastNode.getData (); lastNode = lastNode.getPreviousNode (); if (lastNode == null ) firstNode = null ; else lastNode.setNextNode ( null ); } return last; }...
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