# HW13Sol - Jim Guinns PHYS2212 Assignment #13 Solutions 1. A...

This preview shows pages 1–2. Sign up to view the full content.

Jim Guinn’s PHYS2212 Assignment #13 Solutions 1. A circular coil of wire has 235 loops and a radius of 5.00cm . The coil lies flat on a table (that is, the circular loops are parallel to the table) where there is a 35.0T magnetic field pointing at an angle of 15.0 o up from the horizontal. There is a current of 7.50A in the wire. a.) What is the magnetic moment of the coil? The magnetic moment of a coil is given by Mag. Mom. = N I A = (235) (7.50A) π (5.00x10 -2 m) 2 = 13.8A m 2 . b.) What is the magnitude of the torque on the coil? The torque is given by τ = N I A B sin φ = (13.8A m 2 ) (35.0T) sin(90.0 o - 15.0 o ) = τ = 467N m . 2. At a certain instant of time a particle with charge q = 12 μ C is located at x = 0, y = 2m; its velocity at that time is = (30m/s) . Find the magnetic field at a) the origin; b) x = 0, y = 1m ; c) x = 0, y = 3m ; and d) x = 0, y = 4m . Recall that = ( μ o / 4 π r 2 ) q × , where is the unit vector pointing from the charge q to the observation point P. a)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 01/23/2012 for the course PYSICS 2212 taught by Professor Jimguinn during the Fall '11 term at Georgia Perimeter.

### Page1 / 2

HW13Sol - Jim Guinns PHYS2212 Assignment #13 Solutions 1. A...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online