HW13Sol - Jim Guinns PHYS2212 Assignment #13 Solutions 1. A...

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Jim Guinn’s PHYS2212 Assignment #13 Solutions 1. A circular coil of wire has 235 loops and a radius of 5.00cm . The coil lies flat on a table (that is, the circular loops are parallel to the table) where there is a 35.0T magnetic field pointing at an angle of 15.0 o up from the horizontal. There is a current of 7.50A in the wire. a.) What is the magnetic moment of the coil? The magnetic moment of a coil is given by Mag. Mom. = N I A = (235) (7.50A) π (5.00x10 -2 m) 2 = 13.8A m 2 . b.) What is the magnitude of the torque on the coil? The torque is given by τ = N I A B sin φ = (13.8A m 2 ) (35.0T) sin(90.0 o - 15.0 o ) = τ = 467N m . 2. At a certain instant of time a particle with charge q = 12 μ C is located at x = 0, y = 2m; its velocity at that time is = (30m/s) . Find the magnetic field at a) the origin; b) x = 0, y = 1m ; c) x = 0, y = 3m ; and d) x = 0, y = 4m . Recall that = ( μ o / 4 π r 2 ) q × , where is the unit vector pointing from the charge q to the observation point P. a)
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This note was uploaded on 01/23/2012 for the course PYSICS 2212 taught by Professor Jimguinn during the Fall '11 term at Georgia Perimeter.

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HW13Sol - Jim Guinns PHYS2212 Assignment #13 Solutions 1. A...

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