HW03Sol - Jim Guinns PHYS2212 Assignment #3 Solutions 1. A...

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Jim Guinn’s PHYS2212 Assignment #3 Solutions 1. A parallel-plate capacitor is made of two circular disks of radius 1.00cm that are separated by 2.00mm . The lower plate has a charge of 1.00 μ C, the upper -1.00 μ C . Assume the plates are horizontal and both parallel to the x-y plane with the z-axis passing through their centers and the origin halfway between them as in the diagram. Determine the electric field along the z-axis and plot it from z = 0 to z = 5.00mm . You may use Excel or any graphing program you like. For the bottom plate we have that E z = 2 π k σ {1 – [1 + (10.00mm) 2 /(1.00mm + z) 2 ] -1/2 } and z goes from 0 to 5.00mm . For the upper plate we have that E z = 2 π k σ {1 – [1 + (10.00mm) 2 /(1.00mm - z) 2 ] -1/2 } as z goes from 0 to 1.00mm , but E z = - 2 π k σ {1 – [1 + (10.00mm) 2 /(z - 1.00mm ) 2 ] -1/2 } as z goes from 1.00mm to 5.00mm. The electric field changes for the upper plate because it is always toward the negative plate, to upward when the point is below the plate, and downward when above the plate. The total electric field is then the sum of these components.
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This note was uploaded on 01/23/2012 for the course PYSICS 2212 taught by Professor Jimguinn during the Fall '11 term at Georgia Perimeter.

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HW03Sol - Jim Guinns PHYS2212 Assignment #3 Solutions 1. A...

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