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Unformatted text preview: Principles of Physics 11
PHYS 211211“! Exam #2
Lectures ti n 11
Fall ans Name Saidilhﬂ . H..__.. You may use the values k = sacxlcg a meal, en = 3.35x1c‘l2c3m1n3 , and
e = I_ﬁﬂx1ﬂ‘19 c. 1. (10 points) A pmallelrplate capacitor is made with square plates of side 2.5ﬂmm and
has a plate separation of ﬂ.3llilrnn1 . Ho‘s»r much charge would have to be put on the
capacitor to achieve a voltage of 12.131»? '3' d 3 “I L _ I .5. M C1 ﬂ 9?Erc‘”'c;1 _ (JR513'” no He's—rc r» —r __.__—...u A ‘ NW1" 0.3eotrc'3m Get”; d = 1'. Wire“? ' litor! = lﬂeﬂal'm'ncl 2. {5 points) A capacitor is being charged with a current of 115m . Horar man}:r
electrons are deposited on the capacitor in Sﬂﬂseconds‘? —s
a: :51; : tram324 <5?de : awn: CL . :_ gqrxo‘“al 3. {5 points) Copper 4gauge wire, with a circular cross section, has a diameter of
5. 1 39mm . Horar long must a wire he to have a resistance ofﬁﬁﬂﬂ if copper has a resistiEtyioflﬂilﬂ' [21:2 e ﬂ 5: OIL. 5:]??qoﬂ’l/l 1+
‘52:? J P ‘“ L7 rc'“5’_51 m IL: Blgrjablmr: 3i Lml 4. {It} points] Four charges form the corners of a square with a side length of 4.{lﬂcm .
Three of the charges are lﬂﬂpc and one charge is 3.ﬂl}p.C . What is the potential at the \FenteE oilthe squarekifwe as: Lain at inﬁnity? 3”.“ stern: ﬂ 3#(__
5
.___.—L '"‘ i : ___/—£ II/
P r— r~ dz 7
= LF'J'ID #1 9'5.
V: £99J0qﬂa 1' .Euﬁbqg'l’a a 0H
01" Afgqo'lm IMO if" ’i’ l /Lf: '2'va 5. (It) points) An electric potential has the functional form
Vtx.az}=ex2r+t3rz+txrz, wile: a, B, and Lareconstants. seam is the electric ﬁeld vector Eu, 3', 2)?
v: a at “ 2N aav
V 3W2; " 9’s t.
= vitae194' 33%) +""(_s. stage +5371; 4' E (If?! 4'? 73')
E: — ( integrates); "(0‘ TL? wk”) Q
(ﬁe+3a 9* 6. {it} points) Three charges form the corners of an equilateral triangle with a side
length of 3.ﬂﬂcrn . Two of the charges are 5.0Un‘1C and one ofthe charges are 5.t}t}InC .
What is the potential energy]r of this arrangement if we deﬁne PE=D when all charges are intinitelyfarﬁ'orn each other? a £Wm£
7‘ "a.
PE= he, _ lcg1'__br he ’3,qu
"I: “F” “Tr2Q: 0/ \o
 : 5733‘} ;a‘tum't (gate—Jo 3t)“ _ 5&6 ﬁre“;
a 3 Fbxn‘%
F": flat/ab" T. [lﬂ points] A charge of 2.?5n1C is at the point (1.Uﬂn1 , lﬁﬂm} . 1What is the
potential at the point {2.03m , l.ﬂt}n1) if we deﬁne V=ﬂ at inﬁnity? fa": libD M1”) r:3albm 23%“? r
. e .1 .1 44¢ in
V: kLﬁﬁ‘i‘tJD 10:,35" _:
f C; 'ZJEM IV: 7. raven/l 3. [It] points} An RC circuit has a capacitor with a capacitance of 2.351;!” and an initial
charge of l.ﬂt}n1C . What resistance should be attached across the capacitor so that the
capacitor will discharge to a ﬁnal charge of UffﬁmC in itlﬂseconds? i: '9‘,
13:43.5», A“, aqm=%_ ,ébaﬁtnﬁt— ;
r?” l: :_,___._*j:JJE.S.....__..____ .. 't "t 'E‘l C In (  serum: 9. [15 points] Consider the circuit shown below with the currents as shown. Assume
the voltages and resistances are given. Determine three equations that could he used to
solve for the currents. DD NOT SOLVE THEM! Just ﬁnti the equations. ii}. I: 15 points} Consider the circuit shown below. \
a} What is the current leathtg the battery? V} w, b) What is the current in the 4.1300 resistor? ’0' "TINA
0.73351. I: 18.344 H a) I: $43.23
ﬂ 
0.7m. ISL  *
W gigaiullg'ﬁ] q I
'J'Dﬂ. '
HO I = ISLDU~ $1.5m. 3.13:4
" LLEDJL ...
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This note was uploaded on 01/23/2012 for the course PYSICS 2212 taught by Professor Jimguinn during the Spring '11 term at Georgia Perimeter.
 Spring '11
 JimGuinn

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